Equation limerick competition results
... and the limericks too!

The limericks below are copyright by their authors and are used by permission.

The winners

ln(e⁴) (√1024) + 6(12) - 8(23) = 16

The lon of e to the four
Times the square root of ten twenty-four
Adding six dozen please
Minus eight twenty-three's
Is sixteen, case is closed, shut the door.

Chris Cole

(∫₁³ t³ dt × 7 ) + ( 2 × 11 ) - 2 = 160

The integral of tee cubed dee tee
Starting from one to the number three
Multiplied by seven
Plus two times eleven
Minus two is one hundred sixty

Kim Lu

0 < x < 10   &   9x = (ab)₁₀   &   (a+b) - 5 = 4

tween zero and ten take a number
times it by nine and avoid blunder
then add the two digits
and subtract five from it
to get four, isn't it a wonder

Deeba Khan

$\sum 3$_t=1   (7^t + 3t + 7)/11    =    432/11    ˜    39.3

The sum from t equals one to three
Of seven to the exponent t
PLus three t plus seven
All over eleven
Equals about thirty nine point three

Laura M. Wood

Honourable mention

( √9/1 + 7 + 10 )² - 20 = 380

The square root of nine divided by one
Is added to seven plus ten,
Put wisely in square
Subtracting a score
Becomes multiplication of ten.

Olga Antonova

5log₃9 + 25^-0.5 + √16 + 0.18 = 256^0.5

Let us add the the log of nine times five
To twenty-five to minus point five,
And square root of sixteen,
And zero point eighteen,
Get two five six to zero point five.

Oxana Condracova

μ = 11   &   { [ ( 13 × 2 + 2 ) + 19 × 2 ] / μ } × 7 = 42

A Baker's dozen times then plus two
plus nineteen doubled, all divided by μ
μ is eleven
times all with seven
So the meaning of life is forty-two.

David Henderson

ab₁₀ - (a+b) = 9x

Taking any two digit number
Then simply adding it together
and then subtracting it
from what was started with
is multiples of nine, no wonder!

Deeba Khan

ln(ln(sin(t)))' = cot(t) / ln(sin(t))

When the natural log's twice composed
With itself and sine t, I suppose,
Though complex it may be,
It's derivative, see,
Is cotan by "lawn" sine, so you know.

Michael Lavoie

(∫₁³ t³ dt + 11 - 7 ) × 5 = 120

The integral of tee cubed dee tee
Starting from one to the number three
Adding on eleven
Subtracted by seven
Times five gives you one hundred twenty

Kim Lu

∫ tan⁶(x) sec⁴(x) dx = (1/7)tan⁷(x) + (1/9)tan⁹(x) + C

To integrate tan(x) to the sixth
times the secant squared squared dx predicts
an outcome of (1/7)tan
to the seventh and
(1/9)tan to the nine plus C for a quick fix.

Joanne Sortberg

∫_-1¹ e^arctan(y)/(1+y²) dy = e^π/4 - e^-π/4

To integrate e to arctan(y)
over 1+y² dy and lies
between -1 and 1
shouldbe easily done
as e to π/4 minus e to -π/4

Joanne Sortberg

∫ x²/(x+1) dx = x(½x-1) - x + ln|x+1| + C

To integrate x² over
x+1 dx moreover
can be easily done
as x times ½x-1
minus x + ln|x+1| grover.

Joanne Sortberg

$\int \; t2 \; dt \; = \; 1/3\; \; t3 \; +\; \; C$

The integral of t squared dt
Is a simple problem, you will see
If you just take the time
To read on with this rhyme,
It's just one third of t cubed plus c.

Laura M. Wood

Noteworthy

A mathematician named Erdös
Found proofs that would cause him to sweardös:
"By the hook or the crook
That came straight from the Book!
And I know how they're so very raredös."

Michael Lavoie

3, 4, 5; from this, the theory stems
6, 8, 10; will solve all your problems
There is no where to hide
All these numbers abide
To the Pythagorean Theorem

Linh Phan

The product rule says that, when h(x)
Equals f of x times g of x
The result of h prime
Of x is f(x) times
g prime x plus f prime x g(x)

Tam Nhan

Department of Mathematics

Trent University