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ln(e^{4}) (√1024) + 6(12) - 8(23) = 16

The lon of e to the four

Times the square root of ten twenty-four

Adding six dozen please

Minus eight twenty-three's

Is sixteen, case is closed, shut the door.

*Chris Cole*

(∫_{1}^{3} t^{3} dt × 7 ) + ( 2 × 11 ) - 2 = 160

The integral of tee cubed dee tee

Starting from one to the number three

Multiplied by seven

Plus two times eleven

Minus two is one hundred sixty

*Kim Lu*

0 < x < 10 & 9x = (ab)_{10} & (a+b) - 5 = 4

tween zero and ten take a number

times it by nine and avoid blunder

then add the two digits

and subtract five from it

to get four, isn't it a wonder

*Deeba Khan*

$\sum 3$_{t=1} (7^{t} + 3t + 7)/11
= 432/11 ˜ 39.3

The sum from t equals one to three

Of seven to the exponent t

PLus three t plus seven

All over eleven

Equals about thirty nine point three

* Laura M. Wood*

( √9/1 + 7 + 10 )^{2} - 20 = 380

The square root of nine divided by one

Is added to seven plus ten,

Put wisely in square

Subtracting a score

Becomes multiplication of ten.

*Olga Antonova*

5log_{3}9 + 25^{-0.5} + √16 + 0.18 = 256^{0.5}

Let us add the the log of nine times five

To twenty-five to minus point five,

And square root of sixteen,

And zero point eighteen,

Get two five six to zero point five.

*Oxana Condracova*

μ = 11 & { [ ( 13 × 2 + 2 ) + 19 × 2 ] / μ } × 7 = 42

A Baker's dozen times then plus two

plus nineteen doubled, all divided by μ

μ is eleven

times all with seven

So the meaning of life is forty-two.

*David Henderson*

ab_{10} - (a+b) = 9x

Taking any two digit number

Then simply adding it together

and then subtracting it

from what was started with

is multiples of nine, no wonder!

*Deeba Khan*

ln(ln(sin(t)))' = cot(t) / ln(sin(t))

When the natural log's twice composed

With itself and sine t, I suppose,

Though complex it may be,

It's derivative, see,

Is cotan by "lawn" sine, so you know.

*Michael Lavoie*

(∫_{1}^{3} t^{3} dt + 11 - 7 ) × 5 = 120

The integral of tee cubed dee tee

Starting from one to the number three

Adding on eleven

Subtracted by seven

Times five gives you one hundred twenty

*Kim Lu*

∫ tan^{6}(x) sec^{4}(x) dx
= (1/7)tan^{7}(x) + (1/9)tan^{9}(x) + C

To integrate tan(x) to the sixth

times the secant squared squared dx predicts

an outcome of (1/7)tan

to the seventh and

(1/9)tan to the nine plus C for a quick fix.

*Joanne Sortberg*

∫_{-1}^{1} e^{arctan(y)}/(1+y^{2}) dy
= e^{π/4} - e^{-π/4}

To integrate e to arctan(y)

over 1+y^{2} dy and lies

between -1 and 1

shouldbe easily done

as e to π/4 minus e to -π/4

*Joanne Sortberg*

∫ x^{2}/(x+1) dx = x(½x-1) - x + ln|x+1| + C

To integrate x^{2} over

x+1 dx moreover

can be easily done

as x times ½x-1

minus x + ln|x+1| grover.

*Joanne Sortberg*

$\int \; t2dt\; =\; 1/3\; t3+\; C$

The integral of t squared dt

Is a simple problem, you will see

If you just take the time

To read on with this rhyme,

It's just one third of t cubed plus c.

*Laura M. Wood*

A mathematician named Erdös

Found proofs that would cause him to sweardös:

"By the hook or the crook

That came straight from the Book!

And I know how they're so very raredös."

*Michael Lavoie*

3, 4, 5; from this, the theory stems

6, 8, 10; will solve all your problems

There is no where to hide

All these numbers abide

To the Pythagorean Theorem

*Linh Phan*

The product rule says that, when h(x)

Equals f of x times g of x

The result of h prime

Of x is f(x) times

g prime x plus f prime x g(x)

* Tam Nhan*

Equation Limerick Competition (in pdf format)

MATH 110 Home Page

Department of Mathematics Trent University

Maintained by Stefan Bilaniuk. Last updated 2003.04.28.